1/5x^3+x^2-x-5=0

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Solution for 1/5x^3+x^2-x-5=0 equation: 


x in (-oo:+oo)

(1/5)*x^3+x^2-x-5 = 0

(1/5)*x^3+x^2-x-5 = 0

(1/5)*x^3+x^2-x-5 = 0 // * 0

{ 1, -1, 5, -5, 25, -25 }

1

x = 1

x^3+5*x^2-5*x-25 = -24

1

-1

x = -1

x^3+5*x^2-5*x-25 = -16

-1

5

x = 5

x^3+5*x^2-5*x-25 = 200

5

-5

x = -5

x^3+5*x^2-5*x-25 = 0

-5

x+5

x^2-5

x^3+5*x^2-5*x-25

x+5

-x^3-5*x^2

-5*x-25

5*x+25

0

x^2-5 = 0

DELTA = 0^2-(-5*1*4)

DELTA = 20

DELTA > 0

x = (20^(1/2)+0)/(1*2) or x = (0-20^(1/2))/(1*2)

x = 5^(1/2) or x = -5^(1/2)

x in { -5^(1/2), 5^(1/2), -5} 

x in { -5^(1/2), 5^(1/2), -5 }

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